Merci Posted February 13, 2012 Report Share Posted February 13, 2012 Am I cheating? Maybe I am, but seriously I can't find any question like this on the internet that can help me in solving it. Should it be in this section? Sorry if it shouldn't, but I'm in a bit of a rush here. Also, you guys are smart, right? So I figured you could help me. Ha ha. [i][b]Town A is 16km from town B and its bearing is 132 degrees from B. Town C is 17km from A and its bearing is 069 degrees T from B. What is the bearing of town A from town C?[/b][/i] Link to comment Share on other sites More sharing options...
Catterjune Posted February 13, 2012 Report Share Posted February 13, 2012 Meh. My biggest confusion is the phrase 'it's bearing is [x] degrees from B.' I just plain don't know what it means. I think this is what the question is trying to ask is: [img]http://i.imgur.com/xqIpk.png[/img] Find the red angle, but again, I don't know what 'bearing' means. Sorry. Link to comment Share on other sites More sharing options...
Merci Posted February 13, 2012 Author Report Share Posted February 13, 2012 Well, if it helps, bearing in mathematics is the [i]angle in degrees[/i] measured [i]clockwise from north.[/i] It will thus range between 0 and 360 degrees. <<<<<has no idea what that means. Link to comment Share on other sites More sharing options...
Cin Posted February 13, 2012 Report Share Posted February 13, 2012 It means you need to draw a upward line from the Point C, that will give you the North Point, I wish I remember more from my maths. [i]This diagram is inaccurate because I haven't used the correct distance or angle, you can redraw with them, it's just to give an idea[/i] [img]http://img819.imageshack.us/img819/2064/question2.png[/img] Link to comment Share on other sites More sharing options...
Thar Posted February 16, 2012 Report Share Posted February 16, 2012 [quote name='Merciful Idiot' timestamp='1329129565' post='5814384'] [i][b]Town A is 16km from town B and its bearing is 132 degrees from B. Town C is 17km from A and its bearing is 069 degrees T from B. What is the bearing of town A from town C?[/b][/i] [/quote] I'd help you, but unless I drew it out wrong on AutoCAD, I can only give you the answer. If I knew how to do it algebraically, I'd walk you through it. Link to comment Share on other sites More sharing options...
Sgt. Luna Scar Cautes Posted February 16, 2012 Report Share Posted February 16, 2012 ahh, Bearings in my school, I was top set so It was pretty easy, but Obviously...the sill girl I am, I couldn't wrap my head around it :S But I hope you get the answer and Also I managed a B/A In maths so, I might actually have fluked that question :3 Link to comment Share on other sites More sharing options...
Merci Posted February 16, 2012 Author Report Share Posted February 16, 2012 >.<" So many people who could've known the answer but didn't. Link to comment Share on other sites More sharing options...
CrabHelmet Posted February 16, 2012 Report Share Posted February 16, 2012 Use polar coordinates. Radius = distance; angle = bearing; and points can be written re^(i*theta). Link to comment Share on other sites More sharing options...
Cin Posted February 16, 2012 Report Share Posted February 16, 2012 Merciful I've explained how you can find the answer, I would draw it, but I have no idea where my protractor is. You just need to draw and measure it. Link to comment Share on other sites More sharing options...
Dwarven King Posted February 16, 2012 Report Share Posted February 16, 2012 Basically, it wants the angle between A and C. This circle should help you. [img]http://www.math.com/tables/graphs/unitcircle.gif[/img] Now simple place A, B, and C on their appropriate angles. Then connect them with lines to form a triangle. Lable each line with the correct distance. Then find the angle between A and C. The following link should help you find the correct equation needed to solve this. I would have to draw out the triangle myself in order to know which equation to use, but I have to leave for work here in a few minutes. So either yourself or another member can take a look. ^^ [url="http://www.math.com/tables/graphs/unitcircle.gif"]http://www.math.com/.../unitcircle.gif[/url] Link to comment Share on other sites More sharing options...
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