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~ Math Question of the Day


~ Chidori-Kun

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OneWord: That's what I thought too then Sid said the ! could be 1, but ~Chidori- Kun accidentally put the !.

 

The obvious choices that we have are a. wait for Chidori to clarify b. Do the equation two times using both 14 and 4! c. give up on the problem.

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5z -7 = 13 - z (3z - 1)(6z + 7)

 

5z - 7 = 13 - z(18z^2 + 21z - 6z - 7)

 

5z - 7 = 13 - z(18z^2 + 15z - 7)

 

5z - 7 = 13 - 13z^3 +15z^2 -7z

 

13z^3 - 15z^2 + 12z = 20.

 

Not factorable... Assuming that's how you wanted it, pretty easy.

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