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is anybody good at social studies?

 

it's my worst subject' date=' out of everything

[/quote']

 

Which History are we talking about? I'm good with Government, American History and Japanese History. European History I'm a little weak in.

probably state history

our school focuses on Alabama most of the time

 

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banner!

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solve this. ill give you w reps.

 

Copied from my assignment from the 10th

 

We are given unlimited number of identical, very thin dominoes. The length of a domino is 2 cm and it's mass is neglegable (10 ^ -4314 gram per domino).

Suppose we stack them(assume we are infinitely powerful), one on top of the other, so that the stack advances horizontally in one direction because each is offset a little. the top domino is offset 1cm, and as we move down the stack they are offset progressively less from each other so as to keep the center of gravity. the stack is kept stable only by gravity.

1) show that the stack can advance infinite distance. HINT: numerate the dominoes in a stack from the top. Note that a stack of two dominoes can advance 1cm since the center of the first domino should be above the edge of the second domino. Place the third domino underneath the first two dominoes so that the edge of the third domino is below the center of the stack of the two dominoes that has been built already.

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solve this. ill give you w reps.

 

Copied from my assignment from the 10th

 

We are given unlimited number of identical' date=' very thin dominoes. The length of a domino is 2 cm and it's mass is neglegable (10 ^ -4314 gram per domino).

Suppose we stack them(assume we are infinitely powerful), one on top of the other, so that the stack advances horizontally in one direction because each is offset a little. the top domino is offset 1cm, and as we move down the stack they are offset progressively less from each other so as to keep the center of gravity. the stack is kept stable only by gravity.

1) show that the stack can advance infinite distance. HINT: numerate the dominoes in a stack from the top. Note that a stack of two dominoes can advance 1cm since the center of the first domino should be above the edge of the second domino. Place the third domino underneath the first two dominoes so that the edge of the third domino is below the center of the stack of the two dominoes that has been built already.

[/quote'][align=center]The answer my friend is very simple.

The ratio of the domino is equal to the space-time continuum, if you multiply that by pi and square root it, you will get the answer times e = M©©[/align]

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lawl. u PHAIL!!!! xD

 

answer (with the help of my trusty Scientific calculator, and the looking-back on my answer) is...:d(1)=0

d(2)=1

d(3)=3/2

d(4)=11/6

d(5)=25/12

d(6)=137/60

d(n)= [k=1, n-1]∑(d(k))/(n-1) + 1

 

Now, this is not by itself very illuminating. However, consider the differences between these terms:

 

d(2)-d(1)=1

d(3)-d(2)=1/2

d(4)-d(3)=1/3

d(5)-d(4)=1/4

d(6)-d(5)=1/5

 

Thus, we begin to suspect that the difference between d(n+1) and d(n) is 1/n, and consequently that d(n) = [k=1, n-1]∑(1/k). We shall prove this rigorously by induction:

 

First, we note that this is trivially true for d(2). Suppose it is true for all d(x) where 2 ≤ x ≤ n. Then:

 

d(n+1) = [k=1, n]∑(d(k))/n + 1

= 0+ [k=2, n]∑(d(k))/n + 1

= [k=2, n]∑( [j=1, k-1]∑(1/j))/n + 1

= [k=1, n-1]∑( [j=1, k]∑(1/j))/n + 1

= [k=1, n-1]∑( [j=1, k]∑(1/j))/n + 1

We note that the term 1/1 appears n-1 times in this series, 1/2 appears n-2 times, and so forth, thus:

= [k=1, n-1]∑( (n-k)(1/k))/n + 1

= [k=1, n-1]∑(n/k)/n - [k=1, n-1]∑(k/k)/n + 1

= [k=1, n-1]∑(1/k) - (n-1)/n + 1

= [k=1, n-1]∑(1/k) + 1/n

= [k=1, n]∑(1/k)

 

Thus d(n+1) = [k=1, n]∑(1/k), and by induction, d(n) = [k=1, n-1]∑(1/k) for all n≥2. Thus, the maximum distance which can be spanned by n dominoes is the sum of the first n-1 terms of the harmonic series. However, since the sum of the harmonic series diverges to infinity, so too does the distance spanned by infinitely many dominoes. Q.E.D.

 

(to see that the harmonic series diverges, consider that 1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8... > 1 + 1/2 + (1/4 + 1/4) + (1/8 + 1/8 + 1/8 + 1/8)... = 1 + 1/2 + 1/2 + 1/2 + 1/2..., which clearly diverges to infinity.

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huh?

I really am behind in math, arent I?

Im taking regents in math, the highest level that lets you take some kind of test in 8th grade before even taking it and 9th grade so you can skip a whole year oh math. Basiclly our class learns at twice the rate, learning half of seventh grade and all of the six grade stuff during 6 grade and learning all of 8th grade stuff and the half of seventh grade stuff during seventh grade. and i think we're supposed to learn a algebra thing and you take a test.


dont worry, i got a 92 in ela, im just lazy in spelling and grammer

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Guys, can somebody translate this into French for me? PLEASE?! Stupid clothing unit in French >.>

 

There is my friend Christian. He is wearing a beige hat with an orange feather. It is made by Commodore and the style is classic. It cost $50 dollars.

 

He is also wearing a black sports jacket. It is made by Laltro Vono and the style is cool. It cost $65 dollars.

 

He seems to be wearing a white dress shirt as well. It is made by Christian Dior and the style is classic. It cost $40 dollars.

 

For the final piece, black denim shorts. They are made by Urban Culture and the style is cool. They cost $20 dollars.

 

The total cost of his outfit is $175 dollars.

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I have a perfect reason for applying at June, my fricking teacher is slouching over hard work to me and my classmates.

 

User Name: The Omega

Grade: 5 (Nyeh, I hate that. Age is 11)

Majors in: Reading + Math

Favorite Subjects: Reading & Science

Average: (My basic overall average in all grades?)

 

Also just to tip it off for Freeshooter, I can word that in French.

 

[spoiler=Really long Block of French text]

Il y a mon chrétien d'ami. Il utilise un chapeau beige avec une plume orange. Elle est faite par Commodore et le modèle est classique. Il a coûté $50 dollars. Il utilise également une veste de sports de noir. Elle est faite par Laltro Vono et le modèle est frais. Il a coûté $65 dollars. Il semble utiliser une chemise de robe blanche aussi bien. Elle est faite par Christian Dior et le modèle est classique. Il a coûté $40 dollars. Pour le morceau final, le denim noir court-circuite. Ils sont faits par la culture urbaine et le modèle est frais. Ils ont coûté $20 dollars. Tout le coût de son équipement est de $175 dollars.

 

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